a student throws a heavy ball downward off the top of a building with a speed of 16m/s. The ball reaches a speed of 48m/s just before striking the ground. Neglect drag
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What should we find....
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Answer:
120.40 m
Explanation:
Initial velocity (u) = 16 m/s
Final velocity (v) = 48 m/s
Acceleration (a) = g (gravitational acceleration) = 10m/s²
Displacement (height of the building) (s) = ?
v² = u² + 2gs
∴ s = v² - u² / 2g
= 48² - 16² / 2 * 10
= 2304 - 256 / 20
= 2408 / 20
= 120.40 m
The height of the building is 120.40 m
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