Question

A student took five papers in an examination, where the full marks were the same for each
paper. His marks in these papers were in the proportion of 6 : 7 : 8 : 9 : 10. In all papers
together, the candidate obtained 60% of the total marks. Then the number of papers in which he
got more than 50% marks is
(1) 2 (2) 3 (3) 4 (4) 5

Answer 1

Heyy !! Let the full marks in each subject be 100 then if he obtained 60% it will be 300 then common be x. 300/40 = 7.5 = x. marks are 75 , 67.5 , 60 , 52.5 ,45 answer is 4

Answer 2

Answer:

(3) 4

Step-by-step explanation:

It is given that the marks in these papers were in the proportion of 6 : 7 : 8 : 9 : 10.

Let those marks be 6x, 7x, 8x, 9x and 10x.

Therefore, total marks obtained = 40x.

It is also given that the candidate obtained 60% of the total marks.Therefore, the maximum marks he got = 40x/0.6 = 66.66x.

Hence, maximum marks in each paper = 66.66x/5 = 13.33x

Therefore, for the first paper, percentage = 6x*100/13.33x = 45.01%

For the second paper, percentage = 7x*100/13.33x = 52.52%

For the third paper, percentage = 8x*100/13.33x = 60.01%

For the fourth paper, percentage = 9x*100/13.33x = 67.51%

For the fifth paper, percentage = 10x*100/13.33x = 75.01%

Then the number of papers in which he got more than 50% marks is 4.