Question

A student took four test tubes A,B,C and D each half filled with water. He added one teaspoon full of sugar in test tube A, sand in B, white of egg in C and common salt in D. The contents of the test tube were stirred well and kept undisturbed for sometime. The clear transparent solution will be observed in :
(a) A and B
(b) B and C
(c) C and D
(d) D and A​

Answer 1

Answer:

option d

Explanation:

in test tube A we add sugar, as we know sugar solution is a transparent solution and test tube D we add salt and salt solutio is also a transparent solution

Answer 2

Answer:

The correct answer is option (d)

(d) D and A

The clear transparent solution will be observed in Test tube A and D.

Explanation:

• The clear transparent solution will be observed in test tube A and D. Because salt and sugar completely dissolves in water and forms a true solution.
• In this process the solvent is water and the solute is sugar and salt. When sugar and salt are dissolved separately in water, the positive ions (anions) of water attract the negative ions (cations) of salt and sugar, and also the negative ions present in the water attract the positive ions of salt and sugar.
• In test tube A, the sugar dissolves in water by forming the intermolecular bond between the sucrose (polar) and water molecules (polar)
• In test tube B, the sand does not dissolve in water because the bond present in water cannot dissolve sand. Sand may be dissolved in some strong acids.
• In test tube C, when the egg white is mixed with water it forms a translucent mixture and floats on the surface of the water.
• In test tube D, the salt dissolves in water because the ionic bond present in salt molecules is weaker than the covalent bond present in the water molecules.
• The clear transparent solution will be observed in test tube A and test tube D.

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