A student travel 3/4 speed of its original speed then it get late by 18 minutes what is its original speed.
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Answer:
To find the speed, We need the distance, The question seems incomplete.
Here's the explanation to find the time.
If there's any distance given, Find the speed by dividing it by time. Asap!
Step-by-step explanation:
Let the normal speed be v and time taken by him be t min.
Therefore,
v×t = 3/4v × (t+18)
4t = 3t + 18×3
t= 54 min.
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