Question

A student use lens of focal length 50cm and another student use of -50cm discuss the nature and find the power of lens

Answer 1

■student 1 of focal length 50cm = 0.5 m

p = 1/ f

p = 1/ 0.5

p = 10 / 15

p = 2/3

p = 0.66 m

●as power is positive then the lens is convex and he is suffering from hypermeteropia ...

■student 2 of focal length - 50

p = 1/f

p = -1 / 0.5

p = -10 /15

p = - 0.66 m

●now here as power is negative so the lens is concave and he is suffering from myopia ..

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