Question

A student uses 100cm3 of a 0.2 mole dm3 sodium hydroxide solution to react with excess sulphuric acid.culculate the number of moles of NaOH contained in 100cm3 of solution

Answer 1

Molar mass of NaOH = 23 + 16 + 1 = 40

Mass= 1000/100= 10g of NaOH

No. Of mole of NaOH = mass × molar mass

= 10 × 40 = 400 g/mol