Question

a student uses a heater of resistance 60.5 ohm in his house which is connected to 220V mains. the heater is used daily for 3 hours. find the total monthly bill if the cost of 1 KWH is rupees 2


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Answer 1

a student uses a heater of resistance 60.5 ohm in his house which is connected to 220V mains. the heater is used daily for 3 hours. find the total monthly bill if the cost of 1 KWH is rupees 2

• Answer

Given: V=220V,R=60.5Ω

Power of heater =P=RV2

Energy used in one month=E=Pt=RV2×3×30

⟹E=60.5220×220×90Wh=60.5484×9kWh=72kWh

Hence cost=72×2=Rs144

Answer 2

Answer:

Rs 144

Explanation:

Given: V=220V, R=60.5Ω

Power of heater =P=V^2/R

Energy used in one month=E = Pt = V^2/R ×3 × 30

⟹E=220×220/60.5 ×90Wh=484×9/60.5 kWh=72kWh

Hence cost=72×2=Rs144