a student uses a lens of a focal length 50 cm and another of -50cm. what is the nature of the lens and its power used by each of them?
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As we know that focal length is negative in concave lens so it is a concave lens.
100cm/f. = P
100/ -50 = 2 diopter
100cm/f. = P
100/ -50 = 2 diopter
Deepsh757:
so what is the nature of the lens?
Answered by
2
" Bifocal lens "
Since there are two lens on s single lens with the same focal length. We can say nature of lens to be of bifocal lens.
We have,
f = 50 cm
so, p = 100 / f = 100 / 50 = 2 dipotre.
Note, sign convention shall be on the basis of the focal length.
Since there are two lens on s single lens with the same focal length. We can say nature of lens to be of bifocal lens.
We have,
f = 50 cm
so, p = 100 / f = 100 / 50 = 2 dipotre.
Note, sign convention shall be on the basis of the focal length.
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