A student uses a lens of focal length -30cm. What is the power and nature of this lens?
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p=1/f(in m)
p=100/-30
p=-3.3
ronit06satija:
Pls tell the nature also.
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Power of lens=100/f in cms or 1/f in mts.
Given that focal length of the lens=30cms
Power of lens=100/f cms or 1/f mts.
=100/-30 cms or 1/-30 mts
=3.3
Given that focal length of the lens=30cms
Power of lens=100/f cms or 1/f mts.
=100/-30 cms or 1/-30 mts
=3.3
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