A student uses a lens of focal length 50cm and another of -50cm . what is the nature of the lens and the power used by each of them?
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Answered by
1
Hi mate !
Here is your Answer :
Focal length = +50 cm a lens tells that it is convex lens as it focal length inplus it is .. p= 1/f ( focal length) = +0.02 dioptres
Focal length= -50 cm a lens tells that it is concave lens as it focal length in minus it is p= 1/f ( focal length) = - 0.02 dioptres
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Answered by
2
Answer:
Step-by-step explanation:
F1=50 cm=0.5m(convex)
F2= -50cm= -0.5m(concave)
Now,
P1=1/f1 P2=1/f2
P1=1/0.5 P2=1/ -0.5
P1=2D P2= -2D
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