Physics, asked by sakshimore3007, 5 days ago

A student uses a spring balance of range 500 g wt. He records the weight of a small iron cube of mass 100 g in air, in tap water and in a concentrated solution of common salt in water. His three readings taken in the given order are W, W, and W,. His measurements could be A W =W₂ =W3 , B. W, >W,>W , C. W,< W W W 19 . ​

Answers

Answered by hemanthjayavarapu110
0

Answer:

Weight of iron cube in liquid=weight of iron cube in air−weight of liquid displaced by iron cube The weight of liquid displaced by iron cube depends on the density of the liquid in which it is immersed. Since density of concentrated solution of common salt in water is more than tap water weight(W2) of iron cube in tap water is more than its weight (W3) in common salt solution i.e. W2>W3. Further, as W1>W2:W1>W2>W3.

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