Math, asked by kiwikiwigrapefruit, 11 months ago

A student walks 8 km at v km/h. She then cycles 15 km at 2v km/h. In terms of , solve the time taken in hours
a) When walking
b) when cycling
c) If the total time for the journey is 2 h 35 min, find the girl's walking speed.

Answers

Answered by abhinay365
9

\huge\star\underline\blue {Answer:-}

Given

Distance travelled by walking, d1= 8km

Speed while walking = v km/h

Distance covered by cycling = 15 km

Speed while cycling = 2v km/h

we know

speed =  \frac{distance}{time} \\ time =  \frac{distance}{speed}

a)Walking:-

time =  \frac{8}{v} hrs

b)Cycling:-

time =  \frac{15}{2v} hrs

c)total time:-

total \: time = t1 + t2 \\  =  \frac{8}{v}  +  \frac{15}{2v}  \\  =  \frac{16 + 15}{2v}  \\  =  \frac{31}{2v} hrs

Given time=2hrs35min=2+35/60hrs=155/60=31/12hrs

Hence

 \frac{31}{2v}  =  \frac{31}{12}  \\ 2v = 12 \\ v = 6 \frac{km}{h}

Hence Girl's Walking speed is 6km/h

Hope it helps! ! ! !

Mark my answer as brainliest! ! ! ! !

Regards,

Abhinay.

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