Question

A student walks from his house at 24 km/hr and reaches his school late by
6 minutes. Next day, he increases his speed by 1 km/hr and reaches 6 minutes
before school time. How far is the school from his house?
(S.S.C. 2007)
(a)
km
(6)
7
km
4
(c)
9
km
4
(d)
km​

Answer 1

Perfect ans :

Take a x for his walking time

so A is walking min..

Note : actually time x for distance cover A

now he walk x+6 min for 24 km/h

distance = 24/60 (x+6)

now he walk x min for 25km/h

distance = 25/60 (x-6)

1. in first condition he take more 6 min
2. in second condition he take 6 min less

so we saw both is cover same distance

1st condition = 2nd condition

24/60(x+6) = 25/60 (x-6)

24x + 144 = 25x - 150

25x-24x = 144 + 150

x = 294

@ the 24 km speed take 294 + 6 = 300 min(5 hour )

@ the 25 km speed take 294 - 6 = 288 min ( 4 hour 48 min )

Please Like ...