Question

A student walks from his house at 6:30 a.m. and reaches his school at 7:15 a.m. The distance of the school from his house is 6 kilometres. The speed of the students is

Answer 1

time taken=45min=45/60hours
distance=6km
speed=distance/time
=6/45/60
=6×60/45
=8km/hr
...........hope i answered correctly.....do mark as brainliest if correct

Answer 2

Hello Friend !

The answer to your query is given below. Please refer it !

As given in the question, the student walks from his house at 6:30 a.m. and reaches his school at 7:15 a.m. .

Therefore, the total time taken to reach the school is :

7:15 - 6 : 30 =  45 min. = 45 × 60 = 2700 sec    [ ∵ 1 min = 60 sec  ] 
 
Also, total distance between the school and the home = 6 km = 6 × 1000 = 6000 m     [ ∵ 1 km = 1000 m ]

Now, speed = distance / time

⇒ speed = $\frac{6000}{2700}$ 

⇒ speed = 2.22 m/s ≈ 2 m/s

Or 45 min = $\frac{45}{60}$ hr

⇒ speed =  $\frac{6 km * 60}{45 hr}$ = 8 km/hr

Hope this helps !!!