a student walks from point Ato B at speed of 12 Miles per hour and reaches 5 minutes late. had he walked at 16 miles per hour, he would have been 5 minute early. what is his normal rate of walking.
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Answer:
plz mark brainlist
Step-by-step explanation:
If the required distance be x km, then
x5−x6=30−560
=> 6x−5x30=2560=512
=> x = 30×512
= 12.5 km
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