Chemistry, asked by divyabohra27, 4 months ago

A student wants to prepare a solution of acetic acid and water having
30% v/v. If 6mL
of acetic acid has been taken then how much water must be added to get the desired concentration?​

Answers

Answered by TNShreyaB
0

Answer: 14 mL of water must be added to get desired concentration.

Explanation:

Here solute is acetic acid.

Given: Volume of acetic acid= 6mL

Concentration (v/v) of solution =30%

To find: The amount of water (in mL) needed to get the desired concentration of 30% v/v.

Solution:

Let the volume of water which is the solvent that is needed to get the desired concentration be x.

So, the volume of solution = 6+x

We know the formula,

Concentration of a solution (v/v%) =\frac{Volume   of solute}{Volume   of solution}× 100

\frac{6}{6+x} ×100=30

⇒600=180+30x

⇒30x=600-180

⇒x=\frac{420}{30}

⇒x=14 mL

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