Question

A student wants to project the image of a candle flame on the walls of the school laboratory
by using a mirror.
i) Which type of mirror should he use and why?
ii) At what distance, in terms of focal length 'f' of the mirror, should he place the candle
flame to get the magnified image on the wall?
iii) Draw a ray diagram to show the formation of the image in this case.
iv)Can we use this mirror to project a diminished image of the candle flame on the same wall?state how if your answer is yes and why not if your answer is no.
v)A 5cm tall object is placed at a distance of 30cm from a convex mirror of focal length 15 cm find the position ,size and nature of the image formed.​

Answer 1

Answer:

He should use convex mirror

On the principal axis

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Answer 2

Answer:

A student wants to project the image of a candle flame on the walls of the school laboratory

by using a mirror.

i) Which type of mirror should he use and why?

Answer : The student should use a Concave mirror because a concave mirror produces real images.

ii) At what distance, in terms of focal length 'f' of the mirror, should he place the candle

flame to get the magnified image on the wall?

Answer : To get magnified image, the student should put the candle flame between fand 2f.

iii) Draw a ray diagram to show the formation of the image in this case.

Answer : The ray diagram will be as follows

iv)Can we use this mirror to project a diminished image of the candle flame on the same wall?state how if your answer is yes and why not if your answer is no.

Answer : Yes, concave mirror can be used to obtain a diminished image. When the object is placed beyond 2f, then the image formed will be diminished one.

v)A 5cm tall object is placed at a distance of 30cm from a convex mirror of focal length 15 cm find the position ,size and nature of the image formed.

Solⁿ:

height of object, h = 5cm

object distance from the convex mirror, u = -30

cm

focal length of convex mirror, f= +15cm

now, use formula 1/+1/u = 1/

or, 1/V + 1/-30 = 1/15

or, 1/v = 1/15 + 1/30 = 3/30

or, v = +10cm

hence, position of image is 30 cm right side from

the pole of convex mirror.

magnification = -V/u

height of image/height of object = - (+10)/(-30) =

+1/3

height of image/5cm = 1/3

height of image = 5/3cm = 1.67cm

hence, virtual image is formed by the convex

mirror and the size of image is smaller than size

of object..

–Answer by S_Salik (Naam Toh Suna Hoga)

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