Science, asked by joejeyaraj, 9 months ago

A student was given a mixture containing copper oxide (insoluble) and copper sulphate (soluble) and asked to separate them. Firstly, she stirred the mixture into water, then filtered it. Next, she evaporated the filtrate. a) What substance was the residue in the filtration? b) Describe what the filtrate was. c) what difference in properties allows substances to be separated by filtration d) what difference in properties allowed this seperation

Answers

Answered by DUDESHIVA8320
31

Answer:

a) copper oxide is the residue substance because it is insoluble.

b) Filtrate was copper sulphate because it is soluble substance and its solution in mixture properly.

c)property allowed that copper sulphate is soluble that's all you in the mixture and copper oxide with is not soluble it doesn't mix in the mixtures this is the property of those substances.

d)

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