A student was given a mixture containing copper oxide(insoluble)and copper sulphate (soluble) and asked to separate them. Firstly, she stirred the mixture into water, then filtered it. Next, she evaporated the filtrate.
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Answer:
a) copper oxide is the residue substance because it is insoluble. b) Filtrate was copper sulphate because it is soluble substance and its solution in mixture properly.
Explanation:
Due to slightly non-polar nature of copper oxide, it is insoluble in water whereas copper sulphate is soluble in water. Hence, distilled water should be added to the mixture and the mixture should be filtered to remove copper oxide from it. The filtrate should then be evaporated until the solution is saturated. After few hours of cooling, we will be left with copper sulphate crystals
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