Question

A student who gets 20% marks fails by 10 marks but another student who gets 42% marks gets 12% of maximum marks. Find the maximum marks​

Answer 1

Answer

• Maximum marks = 100

Given

• A student who gets 20 % marks fails by 10 marks but another student who gets 42 % marks gets 12 % more than passing marks .

To Find

• Maximum marks

Solution

Let the maximum marks be " x "

A/c , " A student who gets 20% marks fails by 10 marks but another student who gets 42% marks gets 12%  more than passing marks"

$\rm \implies 20\ \% \times x+10=42\ \% \times x -12\ \% \times x\\\\\implies \rm \dfrac{20}{100} \times x+10=\dfrac{42}{100}\times x-\dfrac{12}{100} \times x\\\\\implies \rm \dfrac{20x+1000}{100}=\dfrac{42x-12x}{100}\\\\\implies \rm 20x+1000=30x\\\\\implies \rm 30x-20x=1000\\\\\implies \rm 10x=1000\\\\\implies \rm x=100$

So , Maximum marks , x = 100

Answer 2

Answer :

The Maximum marks is 100.

Explanation :

Let the maximum marks be x.

According to question

→ 20% of x + 10 = 42% of x - 12% of x

→ 0.20 × x + 10 = 0.42 × x - 0.12 of x

→ 0.20x + 10 = 0.42x - 0.12x

→ 0.20x + 10 = 0.30x

→ 0.30x - 0.20x = 10

→ 0.10x = 10

→ x = 10/0.10

→ x = 10×100/10

→ x = 100

Hence, the Maximum marks is 100.

$\rule{200}{2}$