Physics, asked by incorporated692, 1 year ago

A student who weighs 500 newtons climbed the stairs from the first floor to the third floor, 15 meters above,
in 20 seconds.
a. How much work did she do?
b. What was her power?

Answers

Answered by tamilselvi4496
44

work = 500 x 15 = 7500

power= (500x15)/ 20=375

Answered by handgunmaine
30

Given that,

Weight of the student, W = F = 500 N

She climbed the stairs from the first floor to the third floor 15 meters above, h = 15 m

Time, t = 20 s

To find,

a. Work done

b. Her power

Solution,

(A) When she is climbing from the first floor to the third floor, work done by her s given by :

W=mgh\\\\W=500\times 15\\\\W=7500\ J

(B) Power is given by work done per unit time. So,

P=\dfrac{W}{t}\\\\P=\dfrac{7500\ J}{20\ s}\\\\P=375\ W

Learn more,

Work done

https://brainly.in/question/8637177

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