Question

a student x passes his 10th examination with 515 marks having scored 3%above the minimum. if Y had obtained 710 marks, what percent would have been above the minimum?

Answer 1

let minimum marks = a
marks of X = 515

515= a +(a*3%)
515 = 1.03a
a = 500

Marks of Y = 710
marks above min.=710-500= 210

= 210/500
=0.42
= 42%

Answer = 42%

Answer 2

Y's marks of 710 is 42% above the minimum.

Given that the student X gets 515 marks which is 3% above the minimum marks.

So 515 marks is more than the minimum marks by 3%.

Let the minimum marks be z.

∴ According to the above statement, we can express it as:

(100+3)% of minimum marks = Marks scored by X

⇒ 103% of z = 515

⇒ (103/100) × z = 515

⇒ 1.03z = 515

⇒ z = 515/1.03 = 500

Thus, the minimum marks is 500.

It is given that Y scored 710.

Difference from the minimum marks = 710 - 500 = 210.

Percentage of marks above minimum is express as:

[(Difference/Minimum marks) × 100]%

= [210/500]× 100%

= 0.42 × 100%

= 42%

42% above minimum.