A student X passes his examination with 515 marks, having scored 3% above the minimum.if Y had obtained 710 marks, what% would have been above the minimum?
Answers
Step-by-step explanation:
minimum pass mark = 515 × 100/(100+3)
= 515×100/103
= 500
y's percentage above pass mark
= (710-500)×100/500 %= 210×100/500 % =42
Given : student X passes with 515 marks having scored 3 % above the minimum
student y had 710 marks
To Find : what % would his score have been above the minimum
Solution:
Let say Minimum Score = M
3 % of the minimum = ( 3/100) M = 0.03M
3 % above the minimum = M + 0.03M = 1.03M
1.03M = 515
=> M = 500
student y had 710 marks
=> Marks above minimum score = 710 -500 =210
% above minimum score = (210/500) * 100 = 42 %
Y score 42 % above minimum
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