Question

a student X passes with 618 marks having scored 3 % above the minimum if another student y had 852 marks by what % would his score have been above the minimum
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Answer 1

Given : student X passes with 618 marks having scored 3 % above the minimum

student y had 852 marks

To Find :  what % would his score have been above the minimum

Solution:

Let say Minimum Score  = M

3 % of  the minimum = ( 3/100) M = 0.03M

3 % above the minimum = M + 0.03M = 1.03M

1.03M = 618

=> M = 600

student y had 852 marks

=> Marks above minimum score = 852 - 600 = 252

% above minimum score = (252/600) * 100 = 42 %

Y score 42 % above minimum

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