Question

A students 9.0 V, 7.5W potable radio was left

on from 9:00 P.M. until 3:00 A.M. How much

charge passed through the wires?​

Answer 1

18000 coulomb of charge is passed through the wires.

Explanation:

It is given that,

Voltage, V = 9 V

Power, P = 7.5 W

Time between 9 pm and 3 am is, t = 6 hours = 21600 s

We need to find the charge passed through the wires. We know that power of an electrical device is given by :

$P=V\times I$

$I=\dfrac{P}{V}$

Also, $I=\dfrac{q}{t}$

$\dfrac{q}{t}=\dfrac{P}{V}$

$q=\dfrac{P\times t}{V}$

$q=\dfrac{7.5\times 21600}{9}$

q = 18000 C

So, 18000 coulomb of charge is passed through the wires. Hence, this is the required solution.

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