Question

a students has a set of 176ohm resistors. how many resistor of 176ohm he will connect in parallel with 220volt supply so that the am meter connected by him reads 5ampere on the scale​

Answer 1

For Resistors in Parallel,

1/R(total) = 1/R₁ + 1/R₂ + 1/Rₓ

From Ohm's Law

V = IR

220 = (5)R

R = 44 Ω

Therefore

1/44 = No. of 176Ω Resistors * 1/176

Let no. of 176Ω Resistors be x

Then 1/44 = x/176

x = 4

Therefore, 4 resistors of 176Ω ( in parallel) are required to carry 5 A on a 220 V line.

Answer 2

Answer:

So sorry me apna into dena bhul gyi.

I am Palak

from Maharashtra

class 10th