a students scoref 36% marks then he is failed by 32 marks .But when he score 48% marks he is passed by 64 marks. Find passing %
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Let pass marks be p and total marks be t so,
0.36t = p - 32.......(1)
0.48t = p + 64......(2)
Solving (1) and (2) we get
0.12t = 96
t = 96/0.12
t = 800
Putting t in (1) we get
0.36(800) = p -32
288 = p - 32
p = 320
Therefore pass marks are 320
And pass %age is 320/800 = 40%
0.36t = p - 32.......(1)
0.48t = p + 64......(2)
Solving (1) and (2) we get
0.12t = 96
t = 96/0.12
t = 800
Putting t in (1) we get
0.36(800) = p -32
288 = p - 32
p = 320
Therefore pass marks are 320
And pass %age is 320/800 = 40%
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