Question

A stunt man weighing 80 kg drops himself gently into an open car weighing 720 kg and moving with a
velocity of 80 kmph. Velocity of the car after the event is
[ ]
a) 36 kmph
b) 72 kmph
c) 80 kmph
d) 78 kmph​

Answer 1

Answer:

option B. 72 km/h

Explanation:

initial weight of car(w1)=720 kg

initial velocity(v1)=80km/h

final weight(w2)=720 + 80=800kg

final velocity(v2)=x

w1v1 = w2v2

→720*80=800x

→x = 720 * 80/800

= 72 km/h

Answer 2

Explanation:

here you go mark me as brainlist and thank me