Question

A stunt man weighing 80kg drops himself gently into an open car weighing 720kg and moving with a velocity of 80km/h.the velocity of the car after the event is

Answer 1

Explanation:

initial weight of car=720 kg

initial velocity=80km/h

final weight=720 + 80=800kg

final velocity="x"

according to the condition, they are in inverse proportion.

therefore,

                 720*80=800x

x = 720 * 80/800

x = 72 kilometre per hour

I hope my explanation is clear to you

Answer 2

Answer:

72 Kmph is the answer for the above question