Math, asked by gravywavy53, 2 months ago

A stuntman jumped from an elevation of 500 m and was in free fall before he opened his parachute. His elevation, h meters, t seconds after jumping is modeled by these equations:

h= -4.9t^2+2t+500, before the parachute was opened

h=-5t+188, after the parachute was opened

a) How many seconds after the stuntman jumped did he open the parachute?
b) What was his elevation when he opened the parachute?

Explain your strategy, Give your answers to the nearest tenth of a unit.
Preferably to have answer written out by hand

Answers

Answered by vaishnavisinghscpl45
0

Hello Friend

Good Morning

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