Question

A submarine 9(3)/(4)(It's is a mixed fraction) Metres in height is floating on water.If 1/3 of its height is under water ,then what is the height of the submarine visible above water? ( it's answer is 6(1)/(2)(it is a mixed fraction) J need full explanation. Nd correct answer.
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Answer 1

$\huge \underline\mathcal{ANSWER :-}$

$9 \bold{(3)/(4) \: = 9\huge \frac{3}{4} }$

above hight = total - under

$\implies \bold{ 9 \huge \frac{3}{4} \small \: m - \huge \frac{1}{3} ( \small9 \huge\frac{3}{4}) \small m}$

$\bold{ \implies9 \huge\frac{3}{4} (1 - \frac{1}{3} )m}$

$\implies \huge \bold{ \frac{39}{4} ( \frac{3 - 1}{3})m }$

$\implies\huge \bold{ \frac{ \cancel{39} {}^{13} }{ \cancel{4} {}^{2} } \times \frac{ \cancel2}{ \cancel{3}} }$

$\implies \huge \bold{\frac{13}{2} m}$

$\huge \red \star \bold{ \: 6 \frac{1}{2} \: m }$

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Answer 2

here is your answer buddy