A submarine after traveling 100 km from the shore descended 1 1/10 below the sea level.Then it ascended about 3/5 km.The next day,it again descended by 9/10 km.what is its current position with respect to the sea ? what the horizontal distance of the submarine from the sea shore?
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the submarine descend 1.1 km
then it ascend 0.6 km
again it descend by 0.9 km
therefore its current position will be-
= -1.1 + 0.6 -0.9
=-1.4 km
its current position will be 1.4 km below the sea level
then it ascend 0.6 km
again it descend by 0.9 km
therefore its current position will be-
= -1.1 + 0.6 -0.9
=-1.4 km
its current position will be 1.4 km below the sea level
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