Question

A submarine after travelling 100 km from the shore, descended I.
respect to the sea level? What is the horizontal distance of the submarine from the sea shore?
Exercise 1F
ascended about
km. The next day, it again descended by
5
km below the sea level. Then it
10
km. What is its current position with
10
7
unims. If the chain weighs 26
12​

Answer 1

Answer:

Horizontal displacement = 100 km

Position with respect to sea level = -1.4km

Step-by-step explanation:

Lets take the displacement downwards to be negative displacement and displacement upwards to be positive.

The horizontal distance from the shore remains constant whereas the displacement from the sea level varies as the submarine moves.

The upward displacement = 3/5 km

Downward displacement = - 11/10 km and - 9/10 km

Total displacement = 3/5km - 11/10 km - 9/10km = - 7/5 km = - 1.4 km

Horizontal distance from the shore = 100km