Math, asked by koisvhs, 20 days ago

A submarine dives 320 feet every 2 minutes and 5,600 feet every 35 minutes.

Find the constant rate at which the submarine dives. Enter your answer in feet per minute and feet per hour.

The submarine dives
feet per minute.

The submarine dives
feet per hour.

Answers

Answered by crazybot007
2

\sf\green{HERE'S  \:  \: YOUR  \:  \: ANSWER}

\sf\red{feet \: per \: minute} \\ \sf\pink{ \frac{320}{2} =  \frac{5600}{35}   = 160\: ft \: per \: min}

Since submarines dive quickly, and need to be able

to respond rapidly to sudden changes in conditions,

it is more reasonable to use feet per minute. If we work

in feet per hour at this speed we would need to convert

the data back to feet per minute in order to ensure we

don't dive too deep

\sf\underline{ d_{n} = d_{n - 1}+ 160m}

Where Dn is depth, Dn-1 is previous depth,

and m is number of minutes diving.

r =  \frac{320 }{2} = 160ft \: per \: min \\ r =  \frac{5600}{35 } = 160ft \: per \: min

They should be the same, and they are.

I suppose a submarine dives for a few minutes straight, not hours. If that is so, then ft/min is more practical than ft/hr.

 \sf\red{Mark  \:  \: me  \:  \: as  \:  \: brainliest}

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