Question

a submarine drives at a constant speed of 10 m/s at a diving angle a measured from the vertical of 75 degree if the submarine starts its drive from the surface how deep is the front end of the submarine at the end of 1 minute drive ?

Answer 1

Answer:

Answer:

155.3 m

Step-by-step explanation:

We have:

θ: is the angle measured from the vertical = 75 °

v = is the speed of the submarine = 10 m/s

t = 1 min

The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:

cos (\theta) = \frac{x}{d}cos(θ)=

d

x

Where:

d: is the distance traveled by the submarine in 1 minute

x: is the deep to find

The distance, d, is:

d = v*t = 10 \frac{m}{s}* 1 min * \frac{60 s}{1 min} = 600 md=v∗t=10

s

m

∗1min∗

1min

60s

=600m

Now, the deep is:

cos (75) = \frac{x}{600}cos(75)=

600

x

x = cos(75)*600 = 155.3 mx=cos(75)∗600=155.3m

Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.

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