Question

A submarine emits a sonar pulse, which retum from an underwater cliff in 1.02s . if the speed of sound is salt water is 1531 m/s . how far away is the cliff ?


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Answer 1

Answer:

Speed of sound in sea water, v=1531 m/s.

Distance travelled by sound pulse =2×depth of sea=2d.

Here d means depth of sea

We know that, distance=speed×time

Hence,

2d=Speed of sound×time

=1531 m/s×1.02

=1561.62 m

d=21561.62=780.81 m.

Hence, the cliff is 780.81 m away from the submarine.

Explanation:

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Answer 2

Answer:

Hey friend here is your answer

Explanation:

Speed of sound in sea water, v=1531 m/s.

Distance travelled by sound pulse =2×depth of sea=2d.

Here d means depth of sea

 

We know that, distance=speed×time

Hence,

2d=Speed of sound×time

=1531 m/s×1.02

=1561.62 m

d=21561.62=780.81 m.

Hence, the cliff is 780.81 m away from the submarine.

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