Question

A submarine emits a sonar pulse which returns from an underwater cliff in 2.04 sec. If the speed of sound is seawater is 1531m/s. How far away is that cliff?

Answer 1

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Answer 2

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Time taken by the sonar pulse to return, t = 1.02 s

Speed of sound in salt water, v = 1531 m s−1

Distance of the cliff from the submarine = Speed of sound × Time taken

Distance of the cliff from the submarine = 1.02 x 1531 = 1561.62m

Distance travelled by the sonar pulse during its transmission and reception in water = 2 × Actual distance = 2d

Actual Distance , d = (Distance of the cliff from the submarine)/2 = 1561.62/2 = 780.31 m

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