Question

A submarine enters a sonar pulse which returns from an under water cliff water is 1.02s. if the speed of sound in salt water is 1531m/s how far away is the cliff

Answer 1

Use formula,
d+d = v×t
here d is distance, v is speed of sound and t is time taken. Putting values,
2d = 1531 × 1.02
d = 1561.62/2
distance between cliff and submarine = 780.81m

Answer 2

Solution for ur problem

given
v =1531 m/s
t =1.02s

we know that
2d =v×t
substitute given
2d =1531×1.02
2d= 1561 . 62
then d = 1561.62 ÷2
=780 m

so the cliff is 780 meters away from the submarine

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