a submarine has a circular windows of diameter 0.30m. the windows can experience a maximum external pressure of 660kpa before they crack, find the minimum external force needed to crack the windows
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8
Pressure = Force / Area
Area of the window :
πr²
r = 0.30 / 2 = 0.15 M
3.142 × 0.15² = 0.070695 M²
Pressure = 660 × 1000 = 660000 pa
Force = Pressure × Area
660000 × 0.070695 = 46658.7 N
46658.7 N
Area of the window :
πr²
r = 0.30 / 2 = 0.15 M
3.142 × 0.15² = 0.070695 M²
Pressure = 660 × 1000 = 660000 pa
Force = Pressure × Area
660000 × 0.070695 = 46658.7 N
46658.7 N
sowmiyayahoocom:
can you please help me
Answered by
7
Answer:
Explanation:
Pressure = Force / Area
Area of the window :
πr²
r = 0.30 / 2 = 0.15 M
3.142 × 0.15² = 0.070695 M²
Pressure = 660 × 1000 = 660000 pa
Force = Pressure × Area
660000 × 0.070695 = 46658.7 N
46658.7 N
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