Question

A submarine has gone 4000ft deep into the sea . if it rises at a rate of 30 ft per minute what is the position after 45 minutes?

Answer 1

Answer:

Step-by-step explanation:

INITIAL DEPTH= 4000 FT

RATE OF COMING UP = 30 FT / MIN

DISTANCE MOVE UP IN 45 MIN=?

30 FT RISED IN 1 MIN

IMPLIES , IN 45 MIN RISES UPTO A DISTANCE OF 30*45

DISTANCE RISED UP = 1,350 FT.

NOW THE CURRENT DEPTH OF SUBMARINE = 4,000-1.350

                                                                        =2,650 FT .

HOPE THIS HELPS.

Answer 2

Question is

• A submarine has gone 4000ft deep into the sea . if it rises at a rate of 30 ft per minute what is the position after 45 minutes?

Given in the question is

• A submarine which is 4000ft deep into sea , So the depth is ( from the surface of sea ) = 4000 ft
• Rising speed of sea is = 30 ft / min

So , after 45 mins it will rise a distance can calculated by formula ,

• Speed = Distance / Time

Speed is 30 ft / min , and Given time is 45 min ,

So the distance that it will rise to the top will be ,

• Distance = Speed x Time
• Distance = 30 ft / min x 45 min
• Distance = 30 x 45 ( ft x min / min )
• Distance = 1350 ft

So , it will rise 1350 from bottom of the given depth.

it's position after 45 min is

• 4000 - 1350
• = 2650 ft from surface of water.

More →

if we want to calculate the time during which it can reach the surface then we can apply same formula and method ,

• There Time will be give to measure so we put the values of distance and speed
• Distance = 4000 ft
• Speed = 30 ft / min

Time = Distance / Speed

• = 4000 ft / 30 ft per min
• = 400/3 ( ft x min / ft )
• = 133.3 min