Question

A submarine is 20m below the surface of the sea. The pressure due to the water at this depth
is P
On another day, the submarine is 26 m below the surface of fresh water
The density of sea water is 1.3 times the density of fresh water
What is the pressure due to the fresh water at a depth of 26m?
A. p/13
B. p
C. 1.3P
D. 1.7p​

Answer 1

NANBA..

the answer is 1.7p ..

Hope usefull... ...

Answer 2

Answer:

B

Explanation:

P = Ds g 20h for Sea water at 20m

Sea water density is 1.3 times fresh water, let us consider Ds = 1.3Df

Using Ds for representing sea water density and Df for representing fresh water density

Pf = Df g 20h = Ds/1.3 g 20h for fresh water at 20m

Pf = P/1.3 at 20m

At 26m Pf = (P × 26)/1.3 × 20 = P

Hope this helps