A submarine is a boat that can travel below the surface of the sea.
A submarine is 20m below the surface of the sea. The pressure due to the sea water at this
depth is P.
On another day, the submarine is 26m below the surface of fresh water.
The density of sea water is 1.3 times the density of fresh water.
What is the pressure due to the fresh water at a depth of 26m?
A .P/ 1. 3
B P
C 1.3 P
D 1.7 P
Answers
Answer:
In general p=\rho\cdot g\cdot hp=ρ⋅g⋅h
The pressure due to the fresh water p_0=\rho \cdot g\cdot h_0=\rho \cdot g \cdot 26 \to \rho \cdot g=\frac{p_0}{26}p
0
=ρ⋅g⋅h
0
=ρ⋅g⋅26→ρ⋅g=
26
p
0
The pressure due to the sea water p=1.3\rho \cdot g\cdot h=1.3\rho \cdot g \cdot 20 \to \rho \cdot g=\frac{p}{1.3\cdot26}p=1.3ρ⋅g⋅h=1.3ρ⋅g⋅20→ρ⋅g=
1.3⋅26
p
We have \frac{p_0}{26}=\frac{p}{1.3\cdot26} \to p_0=p
26
p
0
=
1.3⋅26
p
→p
0
=p
So, the pressure will be the same.
Explanation:
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☘ Photosynthesis reaction involves two reactants, carbon dioxide and water. These two reactants yield two products, namely, oxygen and glucose. Hence, the photosynthesis reaction is considered to be an endothermic reaction.
☘ Following is the photosynthesis formula:
6CO2 + 6H2O —> C6H12O6 + 6O2
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