Question

A submarine is at 350 m below sea level .it ascends for 10 seconds and then stops its final position is at 100m below the sea level.find speed of submarine

Answer 1

Answer:

Speed of submarine = 25 m/s

Step-by-step explanation:

Distance below the sea level before ascending = 350 m

After ascending, Distance below the sea level = 100 m

⇒ Total distance = 350 - 100

                            = 250 m  

Time   =   10 sec

$\bf Speed=\frac{Distance}{Time}\\\\\implies Speed = \frac{250}{10}\\\\\implies\textbf{ Speed of submarine = 25 m/s}$    

Answer 2

Step-by-step explanation:

ACCUTIAL DISTANCE OF SUBMARINE=350

FINAL POSITION=100

DISTANCE-FINAL POTION=350-100

250

SPEED=DISTANCE

TIME

SPEED= 250

10

SPEED=25m/s