a submarine is at 350 M below the sea level it as ascends for 10 seconds and then stops. its final position at 100 m below the sea level find the speed of the submarine.
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Total distance = 350 - 100
= 250 m
time = 10 sec
speed = distance / time
= 250 / 10
= 25 m/s
= 90 km/hr
= 250 m
time = 10 sec
speed = distance / time
= 250 / 10
= 25 m/s
= 90 km/hr
ashutosh157:
thanks for answering
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