A submarine is situated 480 feet below the sea level. If it descends 305 feet further, what is its new position? A compact aircraft is flying at the same height from the ground as the submarine is below the sea level now. If the submarine has to destroy the aircraft, how much vertical distance has to be travelled by the torpedo launched by the submarine?
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the position of the submarine = 480feet +305feet = 785feet below the sea level
so the position of aeroplane is 785 feet above the sea level
so the distance torpedo has to travel = 2(785feet)= 1570 feet
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Answer:
1570 feet
Step-by-step explanation:
the position of the submarine = 480feet +305feet = 785feet below the sea level
so the position of aeroplane is 785 feet above the sea level
so the distance torpedo has to travel = 2(785feet)= 1570 feet
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