Question

a submarine limits a sonar Pulse which returns from an underwater diff. in 1.02s. if speed of sound is 1531 m/s. what is the distance of seabed from ship

Answer 1

given,

$t= 1.02s \\ v = 1531 \: mtrs \: per \: sec$
we know that
$v = 2d \div t$
therefore
$d = vt \div 2$
$= > 1531 \times 0.51 \div 2$
$= > 780.81 \: metres$


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