Question

A submarine travels 13 km due East from its base and then turns and travels due North for 3.7 km.
How far away is the submarine from its base?
Give your answer rounded to 1 DP.

Answer 1

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:

129.6 km is far away submarine from its base.

Step-by-step explanation:

We know that,

Hy² = P² + B²

(14.7)² = (9.3)² + (B)²

216.09 = 86.49 + B²

B² = 216.09 - 86.49

B² = 129.69

B = √129.69

B = 11.388

May Help You.

Answer 2

$Summarine \: Travels \: \\ \: 13 km \: East \: and \: \: 3.7 km \: North$

${h}^{2} = {p}^{2} + {b}^{2}$

$( {13)}^{2} = ( {3.7)}^{2} + {b}^{2}$

$169 = 13.69 + {b}^{2}$

${b}^{2} = 169 - 13.69$

${b}^{2} = 155.31$

$b = \sqrt{155.31}$

$b = 12.46$