Math, asked by joannamarybijoy, 8 months ago

A submarine was situated 800 feet below sea level. If it ascends 250 feet, and then descends 50 feet, what is its new position?

Answers

Answered by dhrugupt
0

Step-by-step explanation:

the new height will be 600 Feet

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Answered by k047
3

Let's take sea level as our horizon: if you are on the water surface, your height is h=0 Also, let's assume a vertical axis pointing upwards. This means that the submarine, being 800  feet away from the horizon in the opposite direction with respect to the axis, will have a negative height of  h_{0 } =  - 800.If it ascends 250feets, it gains altitude, so the new height is

h _{1} =  - 800+250= - 550 feet

Note that this problem heavily depends on the coordinate system you adopt. In fact, I may have chosen an axes whose origin is set at the initial position of the submarine (which would have become the  h_{0} = 0 ), pointing upwards, and the new position would have been

 h_{1} = 0 + 250 + 25feet

The only things that won't change is that the new position will be 250"more" than the old one. But if you want to compute absolute values, you need to specify a coordinate system, otherwise you may have as many answers as you want.

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