Question

A subset of an infinite group containing identify is not a grapu itsef

Answer 1

Answer:

It should be pointed out that all of the examples below are "infinitely related", which means that there is no generating set which has a finite set of "rules" which describes how the generators interact. A presentation consists of a set of generators and a list of rules. It is an open problem if there exist infinite, finitely related presented groups all of whose elements have finite order.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Hay Guys!!!!

No, that’s clearly not what it means: a group of size 2 is not an infinite group. You’re to find an infinite group G in which every element except the identity has order 2, meaning that if g∈G, and g is not the identity element 1G of G, then g2=1G. Of course 12G=1G as well, so your problem is really to find an infinite group G in which every element satisfies the equation x2=1G, where 1G is the identity element in G.

HINT: First find a finite group H with this property, and then look at the product of infinitely many copies of H.

Alternative HINT: Consider the operation of symmetric difference on the set of subsets of some infinite set.

Hope it may help you