A substance has a critical angle of 45°for yellow light, what is its refractive index?
Ans=...
Given.
Critical angle ic=45°
Refractive index( miu) =?
We know that..
M(Miu) =1/sinic=1/sin45°
M=√2/1=√2
Therefore. Refractive index of a yellow light is √2..
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Given, Critical angle ic=45°
Refractive index( miu) =?
We know that,
M(Miu) = 1/sinic = 1/sin45°
M = √2/1 = √2
Therefore, Refractive index of a yellow light is √2.
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